It always passes 64 bits, even if it doesn't know anything about the called function. Source code:
#include <stdarg.h> #include <stddef.h> int f(int x, ...); void g(void) { f(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, NULL, 99); }
(Lots of args because if you only have a few they end up in registers instead of on the stack.)
Assembler fragment:
addi r11,r0,15 std r11,160(SP) addi r11,r0,0 std r11,168(SP) addi r11,r0,99 std r11,176(SP)
If you turn on optimization then the assembler is harder to read as things are re-ordered rather, but it's still all std.
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It always passes 64 bits, even if it doesn't know anything about the called function. Source code:
#include <stdarg.h> #include <stddef.h> int f(int x, ...); void g(void) { f(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, NULL, 99); }(Lots of args because if you only have a few they end up in registers instead of on the stack.)
Assembler fragment:
addi r11,r0,15 std r11,160(SP) addi r11,r0,0 std r11,168(SP) addi r11,r0,99 std r11,176(SP)If you turn on optimization then the assembler is harder to read as things are re-ordered rather, but it's still all std.