From zero to hero

[ewx]

[Poll #742287]

Comments

[angoel.livejournal.com]

x^y = e^(y ln x)

=>

0^0 = e^(0 ln 0) = e^0 = 1

[simont]

There's an unjustified step when you multiply 0 by -infinity and get 0.

[bellinghman.livejournal.com]

... when it obviously should be -0.